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URLs provide a [uniform way to locate resources](https://adam.herokuapp.com/past/2010/3/30/urls_are_the_uniform_way_to_locate_resources/). Here's how to parse URLs in Go.
package main
import (
	"fmt"
	"net"
	"net/url"
)
func main() {
We'll parse this example URL, which includes a scheme, authentication info, host, port, path, query params, and query fragment.
	s := "postgres://user:pass@host.com:5432/path?k=v#f"
Parse the URL and ensure there are no errors.
	u, err := url.Parse(s)
	if err != nil {
		panic(err)
	}
Accessing the scheme is straightforward.
	fmt.Println(u.Scheme)
postgres
`User` contains all authentication info; call `Username` and `Password` on this for individual values.
	fmt.Println(u.User)
user:pass
	fmt.Println(u.User.Username())
user
	p, _ := u.User.Password()
	fmt.Println(p)
pass
The `Host` contains both the hostname and the port, if present. Use `SplitHostPort` to extract them.
	fmt.Println(u.Host)
host.com:5432
	host, port, _ := net.SplitHostPort(u.Host)
	fmt.Println(host)
	fmt.Println(port)
host.com
5432
Here we extract the `path` and the fragment after the `#`.
	fmt.Println(u.Path)
/path
	fmt.Println(u.Fragment)
f
To get query params in a string of `k=v` format, use `RawQuery`. You can also parse query params into a map. The parsed query param maps are from strings to slices of strings, so index into `[0]` if you only want the first value.
	fmt.Println(u.RawQuery)
k=v
	m, _ := url.ParseQuery(u.RawQuery)
	fmt.Println(m)
map[k:[v]]
	fmt.Println(m["k"][0])
v
}
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